Optimal. Leaf size=157 \[ -\frac{a^2 (b B-a C)}{b^2 d \left (a^2+b^2\right ) (a+b \tan (c+d x))}-\frac{a \left (a^3 (-C)-3 a b^2 C+2 b^3 B\right ) \log (a+b \tan (c+d x))}{b^2 d \left (a^2+b^2\right )^2}-\frac{\left (a^2 (-C)+2 a b B+b^2 C\right ) \log (\cos (c+d x))}{d \left (a^2+b^2\right )^2}-\frac{x \left (a^2 B+2 a b C-b^2 B\right )}{\left (a^2+b^2\right )^2} \]
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Rubi [A] time = 0.311219, antiderivative size = 157, normalized size of antiderivative = 1., number of steps used = 6, number of rules used = 6, integrand size = 38, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.158, Rules used = {3632, 3604, 3626, 3617, 31, 3475} \[ -\frac{a^2 (b B-a C)}{b^2 d \left (a^2+b^2\right ) (a+b \tan (c+d x))}-\frac{a \left (a^3 (-C)-3 a b^2 C+2 b^3 B\right ) \log (a+b \tan (c+d x))}{b^2 d \left (a^2+b^2\right )^2}-\frac{\left (a^2 (-C)+2 a b B+b^2 C\right ) \log (\cos (c+d x))}{d \left (a^2+b^2\right )^2}-\frac{x \left (a^2 B+2 a b C-b^2 B\right )}{\left (a^2+b^2\right )^2} \]
Antiderivative was successfully verified.
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Rule 3632
Rule 3604
Rule 3626
Rule 3617
Rule 31
Rule 3475
Rubi steps
\begin{align*} \int \frac{\tan (c+d x) \left (B \tan (c+d x)+C \tan ^2(c+d x)\right )}{(a+b \tan (c+d x))^2} \, dx &=\int \frac{\tan ^2(c+d x) (B+C \tan (c+d x))}{(a+b \tan (c+d x))^2} \, dx\\ &=-\frac{a^2 (b B-a C)}{b^2 \left (a^2+b^2\right ) d (a+b \tan (c+d x))}+\frac{\int \frac{-a (b B-a C)+b (b B-a C) \tan (c+d x)+\left (a^2+b^2\right ) C \tan ^2(c+d x)}{a+b \tan (c+d x)} \, dx}{b \left (a^2+b^2\right )}\\ &=-\frac{\left (a^2 B-b^2 B+2 a b C\right ) x}{\left (a^2+b^2\right )^2}-\frac{a^2 (b B-a C)}{b^2 \left (a^2+b^2\right ) d (a+b \tan (c+d x))}+\frac{\left (2 a b B-a^2 C+b^2 C\right ) \int \tan (c+d x) \, dx}{\left (a^2+b^2\right )^2}-\frac{\left (a \left (2 b^3 B-a^3 C-3 a b^2 C\right )\right ) \int \frac{1+\tan ^2(c+d x)}{a+b \tan (c+d x)} \, dx}{b \left (a^2+b^2\right )^2}\\ &=-\frac{\left (a^2 B-b^2 B+2 a b C\right ) x}{\left (a^2+b^2\right )^2}-\frac{\left (2 a b B-a^2 C+b^2 C\right ) \log (\cos (c+d x))}{\left (a^2+b^2\right )^2 d}-\frac{a^2 (b B-a C)}{b^2 \left (a^2+b^2\right ) d (a+b \tan (c+d x))}-\frac{\left (a \left (2 b^3 B-a^3 C-3 a b^2 C\right )\right ) \operatorname{Subst}\left (\int \frac{1}{a+x} \, dx,x,b \tan (c+d x)\right )}{b^2 \left (a^2+b^2\right )^2 d}\\ &=-\frac{\left (a^2 B-b^2 B+2 a b C\right ) x}{\left (a^2+b^2\right )^2}-\frac{\left (2 a b B-a^2 C+b^2 C\right ) \log (\cos (c+d x))}{\left (a^2+b^2\right )^2 d}-\frac{a \left (2 b^3 B-a^3 C-3 a b^2 C\right ) \log (a+b \tan (c+d x))}{b^2 \left (a^2+b^2\right )^2 d}-\frac{a^2 (b B-a C)}{b^2 \left (a^2+b^2\right ) d (a+b \tan (c+d x))}\\ \end{align*}
Mathematica [C] time = 2.05516, size = 324, normalized size = 2.06 \[ \frac{-2 i a \left (a^3 C+3 a b^2 C-2 b^3 B\right ) \tan ^{-1}(\tan (c+d x)) (a+b \tan (c+d x))+a \left (2 (a+i b)^2 (c+d x) \left (i a^2 C+2 a b C-b^2 B\right )+a \left (a^3 C+3 a b^2 C-2 b^3 B\right ) \log \left ((a \cos (c+d x)+b \sin (c+d x))^2\right )-2 C \left (a^2+b^2\right )^2 \log (\cos (c+d x))\right )+b \tan (c+d x) \left (2 (a+i b) \left (a^2 b (B+C (c+d x+i))+i a^3 C (c+d x+i)-a b^2 (B (c+d x+i)-2 i C (c+d x))-i b^3 B (c+d x)\right )+a \left (a^3 C+3 a b^2 C-2 b^3 B\right ) \log \left ((a \cos (c+d x)+b \sin (c+d x))^2\right )-2 C \left (a^2+b^2\right )^2 \log (\cos (c+d x))\right )}{2 b^2 d \left (a^2+b^2\right )^2 (a+b \tan (c+d x))} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.047, size = 313, normalized size = 2. \begin{align*}{\frac{\ln \left ( 1+ \left ( \tan \left ( dx+c \right ) \right ) ^{2} \right ) Bab}{d \left ({a}^{2}+{b}^{2} \right ) ^{2}}}-{\frac{\ln \left ( 1+ \left ( \tan \left ( dx+c \right ) \right ) ^{2} \right ) C{a}^{2}}{2\,d \left ({a}^{2}+{b}^{2} \right ) ^{2}}}+{\frac{\ln \left ( 1+ \left ( \tan \left ( dx+c \right ) \right ) ^{2} \right ){b}^{2}C}{2\,d \left ({a}^{2}+{b}^{2} \right ) ^{2}}}-{\frac{B\arctan \left ( \tan \left ( dx+c \right ) \right ){a}^{2}}{d \left ({a}^{2}+{b}^{2} \right ) ^{2}}}+{\frac{B\arctan \left ( \tan \left ( dx+c \right ) \right ){b}^{2}}{d \left ({a}^{2}+{b}^{2} \right ) ^{2}}}-2\,{\frac{C\arctan \left ( \tan \left ( dx+c \right ) \right ) ab}{d \left ({a}^{2}+{b}^{2} \right ) ^{2}}}-{\frac{{a}^{2}B}{bd \left ({a}^{2}+{b}^{2} \right ) \left ( a+b\tan \left ( dx+c \right ) \right ) }}+{\frac{C{a}^{3}}{{b}^{2}d \left ({a}^{2}+{b}^{2} \right ) \left ( a+b\tan \left ( dx+c \right ) \right ) }}-2\,{\frac{ab\ln \left ( a+b\tan \left ( dx+c \right ) \right ) B}{d \left ({a}^{2}+{b}^{2} \right ) ^{2}}}+{\frac{{a}^{4}\ln \left ( a+b\tan \left ( dx+c \right ) \right ) C}{d \left ({a}^{2}+{b}^{2} \right ) ^{2}{b}^{2}}}+3\,{\frac{{a}^{2}\ln \left ( a+b\tan \left ( dx+c \right ) \right ) C}{d \left ({a}^{2}+{b}^{2} \right ) ^{2}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A] time = 1.67767, size = 266, normalized size = 1.69 \begin{align*} -\frac{\frac{2 \,{\left (B a^{2} + 2 \, C a b - B b^{2}\right )}{\left (d x + c\right )}}{a^{4} + 2 \, a^{2} b^{2} + b^{4}} - \frac{2 \,{\left (C a^{4} + 3 \, C a^{2} b^{2} - 2 \, B a b^{3}\right )} \log \left (b \tan \left (d x + c\right ) + a\right )}{a^{4} b^{2} + 2 \, a^{2} b^{4} + b^{6}} + \frac{{\left (C a^{2} - 2 \, B a b - C b^{2}\right )} \log \left (\tan \left (d x + c\right )^{2} + 1\right )}{a^{4} + 2 \, a^{2} b^{2} + b^{4}} - \frac{2 \,{\left (C a^{3} - B a^{2} b\right )}}{a^{3} b^{2} + a b^{4} +{\left (a^{2} b^{3} + b^{5}\right )} \tan \left (d x + c\right )}}{2 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.30591, size = 682, normalized size = 4.34 \begin{align*} \frac{2 \, C a^{3} b^{2} - 2 \, B a^{2} b^{3} - 2 \,{\left (B a^{3} b^{2} + 2 \, C a^{2} b^{3} - B a b^{4}\right )} d x +{\left (C a^{5} + 3 \, C a^{3} b^{2} - 2 \, B a^{2} b^{3} +{\left (C a^{4} b + 3 \, C a^{2} b^{3} - 2 \, B a b^{4}\right )} \tan \left (d x + c\right )\right )} \log \left (\frac{b^{2} \tan \left (d x + c\right )^{2} + 2 \, a b \tan \left (d x + c\right ) + a^{2}}{\tan \left (d x + c\right )^{2} + 1}\right ) -{\left (C a^{5} + 2 \, C a^{3} b^{2} + C a b^{4} +{\left (C a^{4} b + 2 \, C a^{2} b^{3} + C b^{5}\right )} \tan \left (d x + c\right )\right )} \log \left (\frac{1}{\tan \left (d x + c\right )^{2} + 1}\right ) - 2 \,{\left (C a^{4} b - B a^{3} b^{2} +{\left (B a^{2} b^{3} + 2 \, C a b^{4} - B b^{5}\right )} d x\right )} \tan \left (d x + c\right )}{2 \,{\left ({\left (a^{4} b^{3} + 2 \, a^{2} b^{5} + b^{7}\right )} d \tan \left (d x + c\right ) +{\left (a^{5} b^{2} + 2 \, a^{3} b^{4} + a b^{6}\right )} d\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: AttributeError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.63448, size = 329, normalized size = 2.1 \begin{align*} -\frac{\frac{2 \,{\left (B a^{2} + 2 \, C a b - B b^{2}\right )}{\left (d x + c\right )}}{a^{4} + 2 \, a^{2} b^{2} + b^{4}} + \frac{{\left (C a^{2} - 2 \, B a b - C b^{2}\right )} \log \left (\tan \left (d x + c\right )^{2} + 1\right )}{a^{4} + 2 \, a^{2} b^{2} + b^{4}} - \frac{2 \,{\left (C a^{4} + 3 \, C a^{2} b^{2} - 2 \, B a b^{3}\right )} \log \left ({\left | b \tan \left (d x + c\right ) + a \right |}\right )}{a^{4} b^{2} + 2 \, a^{2} b^{4} + b^{6}} + \frac{2 \,{\left (C a^{4} \tan \left (d x + c\right ) + 3 \, C a^{2} b^{2} \tan \left (d x + c\right ) - 2 \, B a b^{3} \tan \left (d x + c\right ) + B a^{4} + 2 \, C a^{3} b - B a^{2} b^{2}\right )}}{{\left (a^{4} b + 2 \, a^{2} b^{3} + b^{5}\right )}{\left (b \tan \left (d x + c\right ) + a\right )}}}{2 \, d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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